Quantitative Aptitude

Chain Rule: Practice Questions with Answers

14 practice questions on Chain Rule, with answers; most also have an explanation or a worked solution. Try each one before you open its answer.

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  1. Q.1

    36 men can complete a piece of work in 18 days. In how many days will 27 men complete the same work?

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    Answer: 24 days

    Solution:

    1. More men → fewer days (inverse proportion): days = 36 × 18 / 27.
    2. = 648 / 27 = 24 days.

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  2. Q.2

    The cost of 8 pens equals the cost of 6 pencils. If the cost of 10 pencils is ₹150, find the cost of 20 pens.

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    Answer: ₹225

    Solution:

    1. Cost of 1 pencil = 150 / 10 = ₹15, so the cost of 6 pencils = 6 × 15 = ₹90.
    2. The cost of 8 pens equals this: 8 pens = ₹90, so 1 pen = 90/8 = ₹11.25.
    3. Cost of 20 pens = 20 × 11.25 = ₹225.

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  3. Q.3

    If 6 men can earn ₹9,000 in 5 days, how much will 8 men earn in 10 days, at the same daily wage rate per man?

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    Answer: ₹24,000

    Solution:

    1. Earnings scale up directly with both the number of men and the number of days.
    2. New earnings = 9,000 × (8/6) × (10/5) = 9,000 × (4/3) × 2
    3. = 9,000 × 8/3 = ₹24,000.

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  4. Q.4

    If 15 workers can build a wall in 12 days working 8 hours a day, how many days will 18 workers take to build the same wall working 10 hours a day?

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    Answer: 8 days

    Solution:

    1. More workers → fewer days (inverse): multiply by 15/18.
    2. More hours per day → fewer days (inverse): multiply by 8/10.
    3. Days = 12 × (15/18) × (8/10) = 12 × (5/6) × (4/5) = 8 days.

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  5. Q.5

    A garrison of 500 men has food that will last 30 days. After 10 days, 100 more men join. For how many more days will the remaining food last?

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    Answer: ≈ 16.67 days (16 days and 16 hours)

    Solution:

    1. Total food stock = 500 × 30 = 15,000 "man-days".
    2. Used in the first 10 days = 500 × 10 = 5,000 man-days. Remaining = 15,000 − 5,000 = 10,000 man-days.
    3. New headcount = 500 + 100 = 600. Remaining days = 10,000 / 600 ≈ 16.67 days.

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  6. Q.6

    A car covers a certain distance in 5 hours at a speed of 60 km/hr. If the speed is increased to 75 km/hr, find the time taken to cover the same distance.

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    Answer: 4 hours

    Solution:

    1. The distance stays fixed, and speed and time are inversely proportional: time = (5 × 60) / 75.
    2. = 300 / 75 = 4 hours.

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  7. Q.7

    If 20 men can build a 50 m long wall in 12 days, how many days will 15 men take to build a 75 m long wall (at the same rate of work)?

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    Answer: 24 days

    Solution:

    1. Chain the ratios: fewer men → more days (inverse, multiply by 20/15); more wall to build → more days (direct, multiply by 75/50).
    2. Days = 12 × (20/15) × (75/50) = 12 × (4/3) × (3/2)
    3. = 12 × 2 = 24 days.

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  8. Q.8

    20 workers can build a wall in 15 days working 6 hours a day. How many days will 15 workers take to build the same wall working 8 hours a day?

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    Answer: 15 days

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  9. Q.9

    A ship has provisions for 400 passengers for 60 days. After 15 days, 100 passengers leave the ship. For how many more days will the remaining food last?

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    Answer: 60 days. Stock = 24,000 man-days; used = 6,000; remaining = 18,000 ÷ 300 passengers.

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  10. Q.10

    If 25 men can build a 40 m long wall in 16 days, how many days will 20 men take to build a 60 m long wall?

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    Answer: 30 days. 16 × (25/20) × (60/40) = 16 × 1.25 × 1.5.

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  11. Q.11

    15 workers can complete a task in 8 days working 6 hours a day. How many days will 12 workers take, working 10 hours a day?

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    Answer: 6 days. 8 × (15/12) × (6/10).

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  12. Q.12

    24 men can complete a job in 20 days. In how many days will 30 men complete the same job?

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    Answer: 16 days

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  13. Q.13

    The cost of 12 notebooks is ₹180. Find the cost of 20 notebooks.

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    Answer: ₹300

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  14. Q.14

    If 5 men can earn ₹6,000 in 8 days, how much will 10 men earn in 6 days, at the same daily wage rate?

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    Answer: ₹9,000. 6,000 × (10/5) × (6/8).

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How these questions were made

Written by Mahesh Srivastava, Founder of Pariksha Saathi. Published: 2026-10-03.

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