Quantitative Aptitude
Heights and Distances: Practice Questions with Answers
13 practice questions on Heights and Distances, with answers; most also have an explanation or a worked solution. Try each one before you open its answer.
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Q.1
A flagpole stands on top of a 20 m tall tower. From a point on the ground, the angle of elevation of the bottom of the flagpole is 30°, and the angle of elevation of the top of the flagpole is 45°. Find the length of the flagpole.
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Answer: 20(√3 − 1) m ≈ 14.64 m
Solution:
- Let the horizontal distance from the point to the tower be d. From the bottom of the flagpole (top of the tower, height 20): tan 30° = 20/d, so d = 20√3.
- From the top of the flagpole (height 20 + L, where L is the flagpole's length): tan 45° = (20 + L)/d, and since tan 45° = 1, this gives 20 + L = d = 20√3.
- L = 20√3 − 20 = 20(√3 − 1) ≈ 14.64 m.
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Q.2
From a point on the ground, the angle of elevation of the top of a tower is 30°. After walking 20 m towards the tower, the angle becomes 60°. Find the height of the tower.
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Answer: 10√3 m ≈ 17.32 m
Solution:
- Let height = h, and let the original distance be d. From the first position: tan 30° = h/d, so d = h√3.
- From the closer position: tan 60° = h/(d − 20), so d − 20 = h/√3.
- Substitute: h√3 − 20 = h/√3. Multiply through by √3: 3h − 20√3 = h, so 2h = 20√3, giving h = 10√3 ≈ 17.32 m.
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Q.3
A pole casts a shadow of length 10√3 m when the sun’s angle of elevation is 30°. Find the height of the pole.
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Answer: 10 m
Solution:
- tan(30°) = height / shadow length, so height = shadow length × tan(30°).
- tan(30°) = 1/√3, so height = 10√3 × (1/√3) = 10 m.
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Q.4
From the top of a cliff 100 m high, the angle of depression of a boat is 30°. Find the distance of the boat from the base of the cliff.
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Answer: 100√3 m ≈ 173.2 m
Solution:
- The angle of depression from the top equals the angle of elevation from the boat (alternate angles), so tan(30°) = height / distance.
- tan(30°) = 1/√3, so 1/√3 = 100 / distance, giving distance = 100√3 ≈ 173.2 m.
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Q.5
A ladder leans against a wall, making an angle of 60° with the ground. If the foot of the ladder is 5 m from the wall, find the length of the ladder.
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Answer: 10 m
Solution:
- The ladder is the hypotenuse, and 5 m is the side adjacent to the 60° angle: cos(60°) = adjacent / hypotenuse.
- cos(60°) = 1/2, so hypotenuse = 5 / (1/2) = 10 m.
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Q.6
The angle of elevation of the top of a tower from a point 50 m away from its base is 45°. Find the height of the tower.
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Answer: 50 m
Solution:
- tan(45°) = height / distance, so height = distance × tan(45°).
- tan(45°) = 1, so height = 50 × 1 = 50 m.
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Q.7
A flagpole stands on top of a 10 m tall tower. The angle of elevation of the flagpole's bottom is 30°, and of its top is 60°, from the same point. Find the flagpole's length.
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Answer: 20 m. d = 10√3 from the 30° angle; 10 + L = d√3 = 30, so L = 20.
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Q.8
The angle of elevation of the top of a building from a point 40 m away from its base is 45°. Find the height of the building.
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Q.9
From the top of a tower 60 m high, the angle of depression of a car is 45°. Find the distance of the car from the base of the tower.
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Q.10
A tower casts a shadow of length 20√3 m when the sun’s angle of elevation is 30°. Find the height of the tower.
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Q.11
A ladder leans against a wall, making an angle of 60° with the ground. If the foot of the ladder is 6 m from the wall, find the length of the ladder.
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Q.12
From a point on the ground, the angle of elevation of the top of a tower is 30°. After walking 40 m towards the tower, the angle becomes 60°. Find the height of the tower.
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Answer: 20√3 m ≈ 34.64 m. Same method as the worked example, with 40 m instead of 20 m.
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Q.13
A wire of length 20 m is attached from the top of a pole to a point on the ground, making an angle of 30° with the ground. Find the height of the pole.
How these questions were made
Written by Mahesh Srivastava, Founder of Pariksha Saathi. Published: 2026-10-03.