Quantitative Aptitude

Heights and Distances: Practice Questions with Answers

13 practice questions on Heights and Distances, with answers; most also have an explanation or a worked solution. Try each one before you open its answer.

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  1. Q.1

    A flagpole stands on top of a 20 m tall tower. From a point on the ground, the angle of elevation of the bottom of the flagpole is 30°, and the angle of elevation of the top of the flagpole is 45°. Find the length of the flagpole.

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    Answer: 20(√3 − 1) m ≈ 14.64 m

    Solution:

    1. Let the horizontal distance from the point to the tower be d. From the bottom of the flagpole (top of the tower, height 20): tan 30° = 20/d, so d = 20√3.
    2. From the top of the flagpole (height 20 + L, where L is the flagpole's length): tan 45° = (20 + L)/d, and since tan 45° = 1, this gives 20 + L = d = 20√3.
    3. L = 20√3 − 20 = 20(√3 − 1) ≈ 14.64 m.

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  2. Q.2

    From a point on the ground, the angle of elevation of the top of a tower is 30°. After walking 20 m towards the tower, the angle becomes 60°. Find the height of the tower.

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    Answer: 10√3 m ≈ 17.32 m

    Solution:

    1. Let height = h, and let the original distance be d. From the first position: tan 30° = h/d, so d = h√3.
    2. From the closer position: tan 60° = h/(d − 20), so d − 20 = h/√3.
    3. Substitute: h√3 − 20 = h/√3. Multiply through by √3: 3h − 20√3 = h, so 2h = 20√3, giving h = 10√3 ≈ 17.32 m.

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  3. Q.3

    A pole casts a shadow of length 10√3 m when the sun’s angle of elevation is 30°. Find the height of the pole.

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    Answer: 10 m

    Solution:

    1. tan(30°) = height / shadow length, so height = shadow length × tan(30°).
    2. tan(30°) = 1/√3, so height = 10√3 × (1/√3) = 10 m.

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  4. Q.4

    From the top of a cliff 100 m high, the angle of depression of a boat is 30°. Find the distance of the boat from the base of the cliff.

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    Answer: 100√3 m ≈ 173.2 m

    Solution:

    1. The angle of depression from the top equals the angle of elevation from the boat (alternate angles), so tan(30°) = height / distance.
    2. tan(30°) = 1/√3, so 1/√3 = 100 / distance, giving distance = 100√3 ≈ 173.2 m.

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  5. Q.5

    A ladder leans against a wall, making an angle of 60° with the ground. If the foot of the ladder is 5 m from the wall, find the length of the ladder.

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    Answer: 10 m

    Solution:

    1. The ladder is the hypotenuse, and 5 m is the side adjacent to the 60° angle: cos(60°) = adjacent / hypotenuse.
    2. cos(60°) = 1/2, so hypotenuse = 5 / (1/2) = 10 m.

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  6. Q.6

    The angle of elevation of the top of a tower from a point 50 m away from its base is 45°. Find the height of the tower.

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    Answer: 50 m

    Solution:

    1. tan(45°) = height / distance, so height = distance × tan(45°).
    2. tan(45°) = 1, so height = 50 × 1 = 50 m.

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  7. Q.7

    A flagpole stands on top of a 10 m tall tower. The angle of elevation of the flagpole's bottom is 30°, and of its top is 60°, from the same point. Find the flagpole's length.

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    Answer: 20 m. d = 10√3 from the 30° angle; 10 + L = d√3 = 30, so L = 20.

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  8. Q.8

    The angle of elevation of the top of a building from a point 40 m away from its base is 45°. Find the height of the building.

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    Answer: 40 m

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  9. Q.9

    From the top of a tower 60 m high, the angle of depression of a car is 45°. Find the distance of the car from the base of the tower.

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    Answer: 60 m. tan 45° = 60/distance = 1.

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  10. Q.10

    A tower casts a shadow of length 20√3 m when the sun’s angle of elevation is 30°. Find the height of the tower.

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    Answer: 20 m

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  11. Q.11

    A ladder leans against a wall, making an angle of 60° with the ground. If the foot of the ladder is 6 m from the wall, find the length of the ladder.

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    Answer: 12 m

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  12. Q.12

    From a point on the ground, the angle of elevation of the top of a tower is 30°. After walking 40 m towards the tower, the angle becomes 60°. Find the height of the tower.

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    Answer: 20√3 m ≈ 34.64 m. Same method as the worked example, with 40 m instead of 20 m.

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  13. Q.13

    A wire of length 20 m is attached from the top of a pole to a point on the ground, making an angle of 30° with the ground. Find the height of the pole.

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    Answer: 10 m. sin 30° = height/20, so height = 20 × 1/2.

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How these questions were made

Written by Mahesh Srivastava, Founder of Pariksha Saathi. Published: 2026-10-03.

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