Quantitative Aptitude
Simple Equations: Practice Questions with Answers
14 practice questions on Simple Equations, with answers; most also have an explanation or a worked solution. Try each one before you open its answer.
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Q.1
3 pens and 2 pencils cost ₹78. 5 pens and 3 pencils cost ₹128. Find the cost of one pen and one pencil.
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Answer: Pen = ₹22, Pencil = ₹6
Solution:
- Let a pen cost p and a pencil cost q: 3p + 2q = 78 … (1), and 5p + 3q = 128 … (2).
- Scale to eliminate q: multiply (1) by 3 and (2) by 2: 9p + 6q = 234, and 10p + 6q = 256.
- Subtract: p = 256 − 234 = 22. Substitute into (1): 3(22) + 2q = 78 → 66 + 2q = 78 → q = 6.
- Check in (2): 5(22) + 3(6) = 110 + 18 = 128. Matches.
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Q.2
Five years ago, a father was three times as old as his son. Ten years from now, the father will be twice as old as the son. Find their present ages.
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Answer: Father: 50 years, Son: 20 years
Solution:
- Let the son’s present age = s and the father’s present age = f.
- Five years ago: f − 5 = 3(s − 5), so f = 3s − 10.
- Ten years from now: f + 10 = 2(s + 10), so f = 2s + 10.
- Setting these equal: 3s − 10 = 2s + 10, so s = 20, and f = 2(20) + 10 = 50.
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Q.3
A number is 8 more than twice another number. If the sum of the two numbers is 50, find both numbers.
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Answer: 36 and 14
Solution:
- Let the numbers be x and y, with x = 2y + 8.
- Substituting into x + y = 50: (2y + 8) + y = 50, so 3y = 42, giving y = 14.
- Then x = 2(14) + 8 = 36.
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Q.4
If 3 is added to both the numerator and denominator of a fraction, it becomes 3/4. If 1 is subtracted from both, it becomes 1/2. Find the original fraction.
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Answer: 3/5
Solution:
- Let the fraction be x/y. (x+3)/(y+3) = 3/4 → 4x + 12 = 3y + 9 → 4x − 3y = −3 … (1).
- (x−1)/(y−1) = 1/2 → 2x − 2 = y − 1 → y = 2x − 1 … (2).
- Substitute (2) into (1): 4x − 3(2x−1) = −3 → 4x − 6x + 3 = −3 → −2x = −6 → x = 3. Then y = 2(3) − 1 = 5.
- Check: (3+3)/(5+3) = 6/8 = 3/4. (3−1)/(5−1) = 2/4 = 1/2. Both match.
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Q.5
The sum of two numbers is 45, and their difference is 11. Find the two numbers.
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Answer: 28 and 17
Solution:
- Let the numbers be x and y: x + y = 45 and x − y = 11.
- Adding the two equations: 2x = 56, so x = 28.
- Substituting back: y = 45 − 28 = 17.
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Q.6
Three times a number, decreased by 7, equals twice the number increased by 9. Find the number.
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Answer: 16
Solution:
- Let the number be x: 3x − 7 = 2x + 9.
- Subtracting 2x from both sides: x − 7 = 9, so x = 16.
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Q.7
The sum of three consecutive integers is 72. Find the integers.
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Answer: 23, 24, 25
Solution:
- Let the integers be x, x+1, x+2. Their sum: x + (x+1) + (x+2) = 72 → 3x + 3 = 72 → x = 23.
- The integers are 23, 24, 25.
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Q.8
If 2 is added to both the numerator and denominator of a fraction, it becomes 1/2. If 1 is subtracted from both, it becomes 1/3. Find the original fraction.
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Answer: 4/10 (= 2/5). Solve y=2x+2 and y=3x-2 together to get x=4, y=10.
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Q.9
Four times a number, decreased by 9, equals the number increased by 21. Find the number.
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Q.10
The sum of four consecutive integers is 94. Find the largest of the four.
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Q.11
The sum of two numbers is 60, and their difference is 14. Find the two numbers.
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Q.12
A number is 5 more than three times another number. If the sum of the two numbers is 45, find both numbers.
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Q.13
4 notebooks and 3 pens cost ₹84. 3 notebooks and 2 pens cost ₹59. Find the cost of one notebook and one pen.
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Answer: Notebook = ₹9, Pen = ₹16. Eliminate using 2×(first) and 3×(second).
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Q.14
The sum of three consecutive even numbers is 72. Find the numbers.
How these questions were made
Written by Mahesh Srivastava, Founder of Pariksha Saathi. Published: 2026-10-03.