Pariksha SaathiQuantitative Aptitude
Successive Discount: Practice Questions with Answers
14 practice questions on Successive Discount, with answers; most also have an explanation or a worked solution. Try each one before you open its answer.
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Q.1
An item with MRP ₹4000 is sold after three successive discounts of 10%, 20% and 25%. Find the final selling price.
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Answer: ₹2160
Solution:
- After 10%: ₹4000 × 0.90 = ₹3600.
- After 20%: ₹3600 × 0.80 = ₹2880.
- After 25%: ₹2880 × 0.75 = ₹2160.
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Q.2
Using the same item (MRP ₹2000, successive discounts of 20% and 10%), find the single discount percentage that would produce the same final price.
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Answer: 28%
Solution:
- Single equivalent discount = d1 + d2 − (d1 × d2)/100 = 20 + 10 − (20 × 10)/100 = 30 − 2 = 28%.
- Check: ₹2000 × (100 − 28)/100 = ₹1440, which matches the final price from successive discounts.
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Q.3
An item with MRP ₹5,000 is sold after two successive discounts, the first being 20%, for a final price of ₹3,400. Find the second discount percentage.
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Answer: 15%
Solution:
- After the first discount: 5,000 × 0.80 = ₹4,000.
- Let the second discount be d2: 4,000 × (1 − d2/100) = 3,400, so (1 − d2/100) = 3,400/4,000 = 0.85.
- d2 = 15%.
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Q.4
Two successive discounts are applied to an item, the first being 10%. If the overall equivalent single discount is 28%, find the second discount.
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Answer: 20%
Solution:
- Overall multiplier = 1 − 0.28 = 0.72. First discount's multiplier = 1 − 0.10 = 0.90.
- Second discount's multiplier = 0.72 / 0.90 = 0.80, so the second discount = 20%.
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Q.5
An item with MRP ₹2000 is sold after two successive discounts of 20% and 10%. Find the final selling price.
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Answer: ₹1440
Solution:
- After the first discount: ₹2000 × (100 − 20)/100 = ₹1600.
- After the second discount: ₹1600 × (100 − 10)/100 = ₹1440.
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Q.6
A shopkeeper offers two successive discounts of 25% and 10% on an item with MRP ₹4000, instead of a single flat discount of 30%. Which option is cheaper for the customer, and by how much?
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Answer: Successive discounts, by ₹100
Solution:
- Successive discounts: ₹4000 × 0.75 × 0.90 = ₹2700.
- Single 30% discount: ₹4000 × 0.70 = ₹2800.
- The successive discounts give a lower price (₹2700 vs ₹2800) — cheaper for the customer by ₹100.
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Q.7
Find the single discount equivalent to three successive discounts of 10%, 20% and 25%, by combining two at a time.
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Answer: 46%
Solution:
- Combine 10% and 20% first: 10 + 20 − (10×20)/100 = 30 − 2 = 28%.
- Now combine that 28% with the remaining 25%: 28 + 25 − (28×25)/100 = 53 − 7 = 46%.
- Check using multipliers: 0.90 × 0.80 × 0.75 = 0.54, which corresponds to a 46% discount (1 − 0.54 = 0.46). Matches.
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Q.8
An item with MRP ₹1500 is sold after two successive discounts of 10% and 20%. Find the final selling price.
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Q.9
An item with MRP ₹3,000 is sold after two successive discounts, the first being 25%, for a final price of ₹1,800. Find the second discount.
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Answer: 20%. After first discount: ₹2,250; 2,250×(1−d2/100)=1,800 gives d2=20.
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Q.10
An item with MRP ₹6,000 is sold after successive discounts of 15% and 20%. Find the final selling price.
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Q.11
Find the single discount percentage equivalent to two successive discounts of 15% each.
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Q.12
An item with MRP ₹1000 is sold after two successive discounts of 50% each. Find the final selling price (it is NOT free).
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Q.13
Two successive discounts are applied, the first being 20%. If the overall equivalent discount is 28%, find the second discount.
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Q.14
Find the single discount equivalent to three successive discounts of 10%, 10% and 10%, by combining two at a time.
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Answer: 27.1%. Combine first two: 19%; combine 19% with 10%: 19+10−1.9 = 27.1%. Check: 0.9³ = 0.729.
How these questions were made
Written by Mahesh Srivastava, Founder of Pariksha Saathi. Published: 2026-10-05.